Php Simple Log In Videos Tutorials

SteveNI · October 16, 2013

I wonder if someone can help me.

I am following Bens tutorials on building a simple log in system.

I am on the third video and so far I believe I've followed it line by line.

At point 5.30 seconds he refreshes the login page and all the previous errors he had all disappeared, however when I enter the same code I still have the error Notice: undefined variable: error in ...v_login.php on line 18

Like I said I was sure I had followed Ben to the letter, I cannot see where $error is defined in the v_login script, however it seems to work in Bens code.

What could I be doing wrong?

falkencreative · October 16, 2013

Are you following the OOP or non OOP version?

SteveNI · October 17, 2013

Hi Ben

Its the non OOP one

Its the Simple PHP Log in system, with 18 videos on it.

falkencreative · October 17, 2013

Can you post the file you are having trouble with, v_login.php I believe, and I can compare that against my code?

SteveNI · October 17, 2013

Here is my code, I'm taking things a little bit further than you and see this as a registration of a user where we take name, username, password, email etc from the user. Though I should imagine this is the same principle as what you are doing.

Here is my v_login

<html>
   <head>
       <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
       <title>Registration</title>
       <link href="style.css" media="screen" rel="stylesheet" type="text/css"/>
   </head>
   <body>
       <h1>Register</h1>
       <div id="content">
           <form action="" method="post">
               <div>

                   <?php if($error['alert']!='')
                   echo "<div class='alert'>".$error['alert']."</div>"?>

                   <label for="firstname">First Name: * </label>
                   <input type="text" name="firstname" value="<?php echo $input['first'];?>">
                   <div class ="error"><?php echo $error['first'];?></div>
                   <label for="lastname">Second Name: * </label>
                   <input type="text" name="lastname" value="<?php echo $input['last'];?>">
                   <div class ="error"><?php echo $error['last'];?></div>
                   <label for="username">Username: * </label>
                   <input type="text" name="username" value="<?php echo $input['user'];?>">
                   <div class ="error"><?php echo $error['user'];?></div>
                   <label for="password">Password: * </label>
                   <input type="text" name="password" value="<?php echo $input['pass'];?>">
                   <div class ="error"><?php echo $error['pass'];?></div>
                   <label for="password2">Re-Confirm Password: * </label>
                   <input type="text" name="password2" value="<?php echo $input['pass2'];?>">
                   <div class ="error"><?php echo $error['pass2'];?></div>
                   <label for="email">Email: * </label>
                   <input type="text" name="email" value="<?php echo $input['em'];?>">
                   <div class ="error"><?php echo $error['em'];?></div>
                   <p class="required">Required Fields</p>

                   <input type="submit" name="submit" class="submit" value="Submit">
               </div>    
           </form>
       </div>
       <?php

       ?>
   </body>
</html>

Then I have started to create my login.php script as you did, I have echoed what you have done creating input and error variables, though obviously I have more as i have more fields. This is as far as I have got in your tutorial and when you test the code all your errors have disappeared

<?php

//Start session
session_start();
include('config.php');
include('connect-To-db.php');

include('v_login.php');

$error ['alert'] = '';
$error ['first'] = '';
$error ['last'] = '';
$error ['user'] = '';
$error ['pass'] = '';
$error ['pass2'] = '';
$error ['em'] = '';
$input ['first'] = '';
$input ['last'] = '';
$input ['user'] = '';
$input ['pass'] = '';
$input ['pass2'] = '';
$input ['em'] = '';


?>

falkencreative · October 18, 2013

I believe the issue here is the order of your code. within login.php, see how the include() line is before the definition of the $input and $error variables? This means that the view is being loaded too early, and those variables don't exist yet. I believe if you move your include line later within the login.php file, after you define your $errors and $inputs.

Hope that helps?

SteveNI · October 20, 2013

I believe the issue here is the order of your code. within login.php, see how the include() line is before the definition of the $input and $error variables? This means that the view is being loaded too early, and those variables don't exist yet. I believe if you move your include line later within the login.php file, after you define your $errors and $inputs.

Hope that helps?

I have moved the include line below my variables in login.php but I am still getting the Notice: undefined variable: error in ...v_login.php on line 18

Its very frustrating lol!

falkencreative · October 20, 2013

When I test using:

<?php

//Start session
session_start();
include('config.php');
include('connect-To-db.php');

$error ['alert'] = '';
$error ['first'] = '';
$error ['last'] = '';
$error ['user'] = '';
$error ['pass'] = '';
$error ['pass2'] = '';
$error ['em'] = '';
$input ['first'] = '';
$input ['last'] = '';
$input ['user'] = '';
$input ['pass'] = '';
$input ['pass2'] = '';
$input ['em'] = '';

include('view.php');

?>

I don't get any errors. If you want, however, send your files and a dump of your database to ben [at] falkencreative.com, and I'll see if there is something else going on?

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