Jump to content

Recommended Posts

Posted

I'm just trying to get a default value to show up in a form field (type=file) using the example below. Anyone know what I'm missing? I know the variable $imagefile is being populated correctly because I've tested it. Is it just something I'm missing in the html input tag at the bottom?

 

 

 

// above in the php script:

 

if (isset($_GET['id'])) {

$targetID = $_GET['id'];

$sql = mysql_query("SELECT * FROM products WHERE id='$targetID' LIMIT 1");

}

while($row = mysql_fetch_array($sql)){

$imagefile = 'images_folder/' . $targetID . '.jpg';

}

 

 

 

<!-- below in an html form: -->

 

<input type="file" name="fileField" id="fileField" value="<?php echo $imagefile; ?>"/>

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...