Error: Notice: Undefined variable: res.php on lines 362, 408, 412

[Scotty13]

Error: Notice: Undefined variable: res.php on lines 362, 408, 412

(Marked bold below)

 

 

 

Notice: Undefined variable: passengerUserName in /home/************/res.php on line 362

Notice: Undefined variable: passengerFirstName in /home/************/res.php on line 362

Notice: Undefined variable: puname in

/home/************/res.php on line 408

Notice: Undefined variable: pfname in

/home/************/res.php on line 408

Notice: Undefined variable: pcity in

/home/************/res.php on line 412

Notice: Undefined variable: pstate_province in /home/************/res.php on line 412

Notice: Undefined variable: pcountry in

/home/************/res.php on line 412

 

 

$sqlName = mysql_query("SELECT username, firstname FROM myMembers WHERE id='$value' LIMIT 1") or die ("Sorry we had a mysql error!");

 

while ($row = mysql_fetch_array($sqlName)) { $passengerUserName = substr($row["username"],0,12); $passengerFirstName = substr($row["firstname"],0,12);}

 

362 if (!$passengerUserName) {$passengerUserName = $passengerFirstName;} // If username is blank use the firstname programming changes in v1.32 call for this

 

if ($i % 6 == 4){

 

$passengerList .= '<tr><td><div style="width:106px; height:75px; overflow:hidden;" title="' . $passengerUserName . '">

<a href="res.php?id=' . $value . '">' . $passengerUserName . '</a><br />' . $psgr_pic . '

</div></td>';

 

} else {

 

$passengerList .= '<td><div style="width:106px; height:75px; overflow:hidden;" title="' . $passengerUserName . '">

<a href="res.php?id=' . $value . '">' . $passengerUserName . '</a><br />' . $psgr_pic . '

</div></td>';

 

}

 

}

 

$passengerList .= '</tr></table>

 

<div align="right"><a href="#" onclick="return false" onmousedown="javascript:toggleViewAllPassengers(\'view_all_passengers\');">View Manifest</a></div>

 

</div>';

 

// END ASSEMBLE FRIEND LIST TO VIEW UP TO 6 ON PROFILE

 

// ASSEMBLE FRIEND LIST AND LINKS TO VIEW ALL(50 for now until we paginate the array)

 

$i = 0;

$passengerArray50 = array_slice($passengerArray, 0, 50);

$passengerPopBoxList = '<table id="passengerPopBoxTable" width="100%" align="left" cellpadding="6" cellspacing="0">';

foreach ($passengerArray50 as $key => $value) {

$i++; // increment $i by one each loop pass

$check_pic = 'tktedmembers/' . $value . '/image01.jpg';

if (file_exists($check_pic)) {

$psgr_pic = '<a href="res.php?id=' . $value . '"><img src="' . $check_pic . '" width="54px" border="1"/></a>';

 

} else {

 

$psgr_pic = '<a href="res.php?id=' . $value . '"><img src="tktedmembers/0/image01.jpg" width="54px" border="1"/></a>  ';

 

}

 

$sqlName = mysql_query("SELECT username, firstname, country, state_province, city FROM myMembers WHERE id='$value' LIMIT 1") or die ("Sorry we had a mysql error!");

 

while ($row = mysql_fetch_array($sqlName)) { $puname = $row["username"]; $pfname = $row["firstname"]; $pcountry = $row["country"]; $pstate_province = $row["state_province"]; $pcity = $row["city"]; }

408 if (!$puname) {$puname = $pfname;} // If username is blank use the firstname programming changes in v1.32 call for this

if ($i % 2) {

$passengerPopBoxList .= '<tr bgcolor="#F4F4F4"><td width="14%" valign="top">

<div style="width:106px; height:65px; overflow:hidden;" title="' . $puname . '">' . $psgr_pic . '</div></td>

412 <td width="86%" valign="top"><a href="res.php?id=' . $value . '">' . $puname . '</a><br /><font size="-2"><em>' . $pcity . '<br />' . $pstate_province . '<br />' . $pcountry . '</em></font></td>

</tr>';

 

 

Thanks, Scott

[falkencreative]

Personally, I would try changing those lines to use isset() rather than simply checking if the variable is false. So, for example:

 

Original: if (!$passengerUserName)

 

Updated: if (!isset($passengerUserName))

 

Try that and let me know if that fixes it?

[Scotty13]

I added (!isset($passengerUserName)) on line 362 and it removed the first error(Notice: Undefined variable: passengerFirstName in /home/**************/res.php on line 362) other errors still remain. Thanks for your help, new to all this.

[falkencreative]

Correct -- so you need to make that same change for any other "undefined variable" errors, using "!isset()" rather than just "!" like my example above showed.

[Scotty13]

Like this?

 

if(!isset($passengerUserName)){(!isset($passengerUserName)) = (!isset($passengerFirstName));}

 

If so, dosnt work!

[falkencreative]

No, you only need to change the if() portion, and only on the lines where you are running into undefined variable errors. Follow my example:

 

Original: if (!$variable_name)

 

Updated: if (!isset($variable_name))

[Scotty13]

No, you only need to change the if() portion, and only on the lines where you are running into undefined variable errors. Follow my example:

 

Original: if (!$variable_name)

 

Updated: if (!isset($variable_name))

 

This is like Algebra, its there but I just dont see it. This is what I have...

 

if(!isset($passengerUserName)) {(!isset($passengerUserName)) = (!isset($passengerFirstName;))}

[falkencreative]

Your code

 

if(!isset($passengerUserName)) {(!isset($passengerUserName)) = (!isset($passengerFirstName;))} 

needs to go back to

 

if(!isset($passengerUserName)) { $passengerUserName = $passengerFirstName; } 

Take line 408, for example:

 

if (!$puname) {$puname = $pfname;}

you need to modify the if() portion to use isset() like so:

 

if (!isset($puname)) {$puname = $pfname;}

You don't need to change anything within the { ... } section. Anywhere you get the "undefined variable" error, you're probably having the same situation -- you are trying to access a variable that doesn't exist. Using isset() allows you to check if the variable is set and avoid those errors.