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prajakta29

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Posts posted by prajakta29

  1. check all checkbox

    in Javascript

    Posted

    hello everybody...

    facing a simple problem.what is the format to make all check-boxes check in particular category..

    i have 3-4 categories in my code.n i have created a function check all which will select all check-boxes.bt the problem is that i want to create three separate functions for each category which can select only check boxes belonging to that category...

    what is the format in js..

    here is part of my code

     

    // function check all which select all checkboxes

    function chkall()

    {

    for(i=0; i<document.selectlist.elements.length; i++)

    {

    if (document.selectlist.elements.checked==false)

    {

    document.selectlist.elements.checked=true;

    }

    }

     

     

     

    //php n html coding

     

     

    <form name="selectlist" action="calledlistpg.php?requestid=<? echo $requestid?>&clientid=<? echo $clientid ?>&page=<? echo $page ?>" method="post">

     

     

    echo"<td><input type='checkbox' name='chkselectmodel[]' value='$regid'></td>";

    echo "<td><input type='checkbox' name='chkselectmodelpics[]' value='$regid'></td>";

    echo "<td><input type='checkbox' name='chkselectmodelmsg[]' value='$regid'></td>";

    echo "<td><input type='checkbox' name='chkselectmodelng[]' value='$regid'></td>";

     

     

    //cz of checkall function all checkboxes are getting selected...i want to create 3 more functions like checkall which will individualy select chkselectmodelpics[],chkselectmodelmsg[],chkselectmodelng[]

     

     

     

     

    I hope u got my prb...any help is appreciable...thanks

  2. display images on word document

    in PHP

    Posted

    hie everyone....

    i want to display images on word document thru php coding... i have successfully generated the word document evn it is displaying all other data from database except images...it is showing the path on word page instead of image...

    whats the problem...i have used the same path of images in other applications to display images....

    <?php mysql_connect ("abc","web","peter");

    mysql_select_db("inmatch");

     

    $requestid=$_GET['requestid'];

    $clientid=$_GET['clientid'];

     

     

     

    $query="select RM.RegID,P.Blowup from shortlist MT, registration_male RM,photo P WHERE MT.RequestID='$requestid' AND MT.ClientId=$clientid AND MT.RegID=RM.RegID AND P.RegID=RM.RegID ";

    $result=mysql_query($query);

     

    $str="<table width='50%' border='1' align='center'><tr><td>RegID</td><td>Photo</td></tr>";

     

    while ($row=mysql_fetch_array($result))

    {$regid=$row[0];

    $blow=$row[1];

     

     

    if($regid)

    $objectIndex = "PHT";

    $whereclause = " WHERE RegID=".$regid;

    $otherclause = "";

    $fields = "PhotoID, BlowUp, DisplayType, RegID";

    //$result_array = _getRows($objectIndex, $fields, $whereclause, $otherclause);

     

    $result_array="select ".$fields. "from" .$objectIndex."where" .$whereclause;

    $blowup_indx = 1;

    $regid_indx = 3;

    {

    for($i=0;$i<count($result_array);$i++)

    {

     

     

    $photo='<img src=//192.168.0.2/site/inmatch /photographs/ . $result_array[$i][$blowup_indx] >';

     

    $str.="<tr><td>$regid</td><td>$photo</td></tr>";

     

    }}}

    $str.="</table>";

     

    header("Content-type: application/vnd.ms-word");

    header("Content-Disposition: attachment;Filename=shortlisedpics.doc");

    echo $str;

    exit;

    ?>

    plss rep me as soon as possible...

  3. display images on word document

    in PHP

    Posted · Edited by prajakta29

    hie everyone....

    i want to display images on word document thru php coding... i have successfully generated the word document evn it is displaying all other data from database except images...it is showing the path on word page instead of image...

    whats the problem...i have used the same path of images in other applications to display images....

    <?php mysql_connect ("abc","web","peter");

    mysql_select_db("inmatch");

     

    $requestid=$_GET['requestid'];

    $clientid=$_GET['clientid'];

     

     

     

    $query="select RM.RegID,P.Blowup from shortlist MT, registration_male RM,photo P WHERE MT.RequestID='$requestid' AND MT.ClientId=$clientid AND MT.RegID=RM.RegID AND P.RegID=RM.RegID ";

    $result=mysql_query($query);

     

    $str="<table width='50%' border='1' align='center'><tr><td>RegID</td><td>Photo</td></tr>";

     

    while ($row=mysql_fetch_array($result))

    {$regid=$row[0];

    $blow=$row[1];

     

     

    if($regid)

    $objectIndex = "PHT";

    $whereclause = " WHERE RegID=".$regid;

    $otherclause = "";

    $fields = "PhotoID, BlowUp, DisplayType, RegID";

    //$result_array = _getRows($objectIndex, $fields, $whereclause, $otherclause);

     

    $result_array="select ".$fields. "from" .$objectIndex."where" .$whereclause;

    $blowup_indx = 1;

    $regid_indx = 3;

    {

    for($i=0;$i<count($result_array);$i++)

    {

     

     

    $photo='<img src=//192.168.0.2/site/inmatch /photographs/ . $result_array[$i][$blowup_indx] >';

     

    $str.="<tr><td>$regid</td><td>$photo</td></tr>";

     

    }}}

    $str.="</table>";

     

    header("Content-type: application/vnd.ms-word");

    header("Content-Disposition: attachment;Filename=shortlisedpics.doc");

    echo $str;

    exit;

    ?>

  4. photo gallery in php

    in PHP

    Posted

    You couldadd some php logic to make that work. Typically, the highslide just need the class="highslide" assigned to whatever image you extract from the database. The highslide script handles the rest.

    i got the solution...now its working properly with the help of jquery...was facing prob in highslide while displaying those image

  5. hiding html tags

    in PHP

    Posted

    Try to use it around the $something = $_POST['something'];

     

    So itwill be $something = strip_tags($_POST['something']);

     

    Hope it works.

    I tried this already but nt resolving the problem:-(

  6. jQuery photo gallery

    in Beginners Web Design

    Posted

    Best solution I would suggest would be to go for a popular CMS like Joomla or Wordpress. There are dozens of great gallery components or plugins for each.

     

    thanks for the suggestion...but the thing is i have very less tym to coverup ths topic so it will take lil bit more tym to implement zoomla n all in php codes...

    i got the code with small error.

    m posting a part of that code which is getting affected.

     

    $objectIndex = "PHT";

    $whereclause = " WHERE RegID=".$regid;

    $otherclause = "";

    $fields = "PhotoID, BlowUp, DisplayType, RegID";

    $result_array = _getRows($objectIndex, $fields, $whereclause, $otherclause);

     

    $photoid_indx = 0;

    // ThumbNail, $thumbnail_indx = 1;

    $blowup_indx = 1;

    $disptype_indx = 2;

    $regid_indx = 3;

    if($regid)

    {

    $photo1=$result_array[$blowup_indx];

     

     

    $aphotopath1 = "../photographs/".$result_array[$regid_indx][$blowup_indx];

    $result_array[$blowup_indx]++;

     

    $photo2=$result_array[$blowup_indx];

    $aphotopath2 = "../photographs/".$result_array[$regid_indx][$blowup_indx];

    $result_array[$blowup_indx]++;

     

    $photo3=$result_array[$blowup_indx];

    $aphotopath3 = "../photographs/".$result_array[$regid_indx][$blowup_indx];

    $result_array[$blowup_indx]++;

     

     

     

     

    <div class="album" align ="center">

    <h2 align="center">1</h2>

    <a href="<?php echo $aphotopath1 ?>"><img src="<?php echo $aphotopath1 ?>" alt="" /></a>

     

     

    </div>

    <div class="album">

    <h2 align="center">2</h2>

    <a href="<?php echo $aphotopath2 ?>"><img src="<?php echo $aphotopath2 ?>" alt="" /></a>

     

    </div>

    <div class="album">

    <h2 align="center">3</h2>

    <a href="<?php echo $aphotopath3 ?>"><img src="<?php echo $aphotopath3 ?>" alt="" /></a>

     

    </div>

     

     

     

    now the thing happening is m getting the first image only for all images like 2,3,4....

    i have stored images in blowup column in mysql(wamp) database

    the actual thing that has to take place is each tym blowup should b increased by one and will display next image for same regId....

    i hope m putting it in rite way...jst tell me whr shud i correct

  8. jQuery photo gallery

    in Beginners Web Design

    Posted

    m new in jQuery's concept. actually i wanted to add a code to view images extracted from database but m nt getting the solution in php so m tryng to work on jQuery... I dont have any idea abt it...plss suggest me some code to view prev nxt images of a user from database....

  9. photo gallery in php

    in PHP

    Posted

    hi everyone!

    in my project i want to create a gallery...there are many pictures present on a page. By clicking on one image a windw opens which enlarges the image..show it in proper size..now the problem occuring is that if i want to see any pic i need to cancle the prev pic's window. i want to create prev and next link which can help me to view all pics without closing that window... It is very simple to understand but m nt able to sort it out.its same like jpeg images that we select in pc.v can c next images n prev also...

    all image info is stored in database like photoid,regid,blowup n all.

     

    help me with any link whch can open an image and i can add nxt prv buttons to it

    fast...its quite urgent

  10. hiding html tags

    in PHP

    Posted

    Hi friends

    I am working on back end system developed in php..I am facing a very simple n silly problem...but m nt getting it exactly so just help me if u can...ny help is appreciable...

    At backend i can modify user's profile which will be displayd on site after my updation...now while writing the profile info i use some html tags like <br><b> and close them properly too....but problem is that after updation,on site all these tags r visible to viewers.... i hope u all get my problem... code is in php...plss g sm soln.

    i used strip_tags() function in <?php echo strip_tags($moreabtu); ?>

    but i got this error

    Failed Query of UPDATE user_master set personaldescpdesc ='A I am a kathhak dancer .' WHERE userid=403115

  11. RETRIVE DROPDOWN RESULT WHILE EDITING IN PHP

    in PHP

    Posted

    It looks like you have the right general idea. You need to create a variable that will hold your dropdown's value, and then compare that value against the option's value to figure out which is correct.

     

    <select name="shoot_month" class="form1"><option value="00">-Select-</option>

<option value="01"<?php if ($shootarr[1]=="01") echo "selected";?>>January</option>
<option value="02"<?php if ($shootarr[1]=="02") echo "selected";?>>February</option>
<option value="03"<?php if ($shootarr[1]=="03") echo "selected";?>>March</option>
<option value="04"<?php if ($shootarr[1]=="04") echo "selected";?>>April</option>
<option value="05"<?php if ($shootarr[1]=="05") echo "selected";?>>May</option>
<option value="06"<?php if ($shootarr[1]=="06") echo "selected";?>>June</option>
<option value="07"<?php if ($shootarr[1]=="07") echo "selected";?>>July</option>
<option value="08"<?php if ($shootarr[1]=="08") echo "selected";?>>August</option>
<option value="09"<?php if ($shootarr[1]=="09") echo "selected";?>>September</option>
<option value="10"<?php if ($shootarr[1]=="10") echo "selected";?>>October</option>
<option value="11"<?php if ($shootarr[1]=="11") echo "selected";?>>November</option>
<option value="12"<?php if ($shootarr[1]=="12") echo "selected";?>>December</option>
</select>

    This code looks fine (I usually use "selected="selected"" and add a space between that and the value, but that's up to you), assuming your $shootarr array is set up properly. You might want to try displaying your array values such as $shootarr[1] on the page to make sure they are holding the values you expect.

     

    After looking over your code again, where do you define the $postarr and $shootarr arrays? I see that you try to access them (for example, in your code above) but I don't see where you create those variables and set their values.

    i used yr suggested code.but it is displaying first value of the array. this is the portion where i defined postarr and shootarr in mou.php. this file adds new entry.

    $srno=$_GET['Sr_no'];

    $mou="";

    $name="";

    $day = "";

    $date="";

    $coord="";

    $client="";

    $tel="";

    $mob="";

    $fb="";

    $sex="";

    $sell="";

    $firstadvance="";

    $balreceived="";

    $shootreceived="";

    $rolls="";

    $cheque="";

    $shootdate="";

    $postshoot="";

     

    if(!empty($srno) && isset($srno)){

    $objectIndex = "SD";

    $fields = _getFields("MF");

     

    $whereclause = "WHERE Sr_no=$srno" ;

    $otherclause = "";

    $result_array = _getRows($objectIndex, $fields, $whereclause, $otherclause);

     

     

     

    if(!empty($result_array)){

    for($i=0;$i<count($result_array);$i++)

    {

     

    $srno=$result_array[$i][0];

    $mou=$result_array[$i][1];

    $name=$result_array[$i][2];

    $day =$result_array[$i][3];

    $date=$result_array[$i][4];

    $datearr=split('[-/]',$date);

    $coord=$result_array[$i][5];

    $client=$result_array[$i][6];

    $tel=$result_array[$i][7];

    $mob=$result_array[$i][8];

    $fb=$result_array[$i][9];

    $sex=$result_array[$i][10];

    $sell=$result_array[$i][11];

    $firstadvance=$result_array[$i][12];

    $balreceived=$result_array[$i][13];

    $shootreceived=$result_array[$i][14];

    $rolls=$result_array[$i][15];

    $cheque=$result_array[$i][16];

    $shootdate=$result_array[$i][17];

    $shootarr=split('[-/]',$shootdate);

    $postshoot=$result_array[$i][18];

    $postarr=split('[-/]',$postshoot);

    }

    }

     

    }

    ?>

     

     

    all data is saved thru save_mou.php....in this

     

    sign_date=$_POST['sign_date'];

    $sign_year=$_POST['sign_year'];

    $sign_month=$_POST['sign_month'];

    $date=$sign_year."-".$sign_month."-".$sign_date;

     

    $shoot_date=$_POST['shoot_date'];

    $shoot_month=$_POST['shoot_month'];

    $shoot_year=$_POST['shoot_year'];

    $shootdate=$shoot_year."-".$shoot_month."-".$shoot_date;

     

    $post_date=$_POST['post_date'];

    $post_month=$_POST['post_month'];

    $post_year=$_POST['post_year'];

    $postshoot=$post_year."-".$post_month."-".$post_date;

     

    $srno=$_POST["srno"];

    $mou=$_POST["mou"];

    $name=$_POST["name"];

    $day = $_POST["day"];

    $date=$_POST['sign_year']."-".$_POST['sign_month']."-" .$_POST['sign_date'];

    $coord=$_POST["coord"];

    $client=$_POST["client"];

    $tel=$_POST["tel"];

    $mob=$_POST["mob"];

    $fb=$_POST["fb"];

    $sex=$_POST["arr_sex"];

    $sell=$_POST["sell"];

    $firstadvance=$_POST["firstadvance"];

    $balreceived=$_POST["balreceived"];

    $shootreceived=$_POST["shootreceived"];

    $rolls=$_POST["arr_roll"];

    $cheque=$_POST["cheque"];

    $shootdate=$_POST['shoot_year']."-".$_POST['shoot_month']."-" .$_POST['shoot_date'];

    $postshoot=$_POST['post_year']."-".$_POST['post_month']."-" .$_POST['post_date'];

     

     

    now suggest me something..if u r nt getting the code..plss tell me yr ideas...i'l try to implement it

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