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Date transforms 0000-00-00 to 01-01-1970 please help to fix it


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Posted

column Name: secondgirld

Datatype:date

 

To echo the date in "d-m-Y" format i am using the below code

echo date("d-m-Y", strtotime($row['secondgirld']));

 

There is no problem when secondgirld is not equal to empty (secondgirld!='')

 

when secondgirld field is empty (that is:secondgirld=='') it stores value as 0000-00-00 in mysql.

But echo date("d-m-Y", strtotime($row['secondgirld']));

shows 01-01-1970.

 

please help to fix this problem.

I just want to display a blank field or 00-00-0000

Posted

column Name: secondgirld

Datatype:date

 

To echo the date in "d-m-Y" format i am using the below code

echo date("d-m-Y", strtotime($row['secondgirld']));

 

There is no problem when secondgirld is not equal to empty (secondgirld!='')

 

when secondgirld field is empty (that is:secondgirld=='') it stores value as 0000-00-00 in mysql.

But echo date("d-m-Y", strtotime($row['secondgirld']));

shows 01-01-1970.

 

please help to fix this problem.

I just want to display a blank field or 00-00-0000

 

 

strtotime returns boolean false when '0000-00-00' is passed to it. When false is provided as the second parameter in date() it returns 01-01-1970.

 

If I were you, I would do something like:

if ($row['secondgirld'] == '0000-00-00')
{
 echo '';
} else
{
 echo date('m-d-Y', strtotime($row['secondgirld']));
}

Posted

strtotime returns boolean false when '0000-00-00' is passed to it. When false is provided as the second parameter in date() it returns 01-01-1970.

 

If I were you, I would do something like:

if ($row['secondgirld'] == '0000-00-00')
{
 echo '';
} else
{
 echo date('m-d-Y', strtotime($row['secondgirld']));
}

 

Another one:

 

DATE_FORMAT(`secondgirld`,'%d-%m-%Y') AS secondgirld

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