sbsmith Posted December 4, 2011 Report Share Posted December 4, 2011 (edited) Hi I'm hoping someone here can help me resolve this problem. I think I'm almost there I'm just missing something that I've overlooked. What I'm trying to do is create one custom MySQL table out of 3 existing MySQL Tables. This is what I've come up with... SELECT proj.p_id, proj.p_name, proj.p_status, COUNT(domain) AS domain_count, SUM(IF(pt_status = 3 , 1, 0 )) AS published_posts, SUM(IF(pt_status = 2 , 1, 0 )) AS approved_posts, SUM(IF(pt_status = 1 , 1, 0 )) AS queued_posts, SUM(IF(pt_status < 1 , 1, 0 )) AS declined_posts FROM wp_cglg_projects proj LEFT JOIN wp_cglg_domains d ON proj.p_id = d.project_id LEFT JOIN wp_cglg_posts pt ON d.d_id = pt.domain_id GROUP BY proj.p_id; The statement above produces the table I want except the domain count in my first row is incorrect. It should be 2 not 3. 1. Below is picture of my Custom Table... Here is a picture of my existing 3 tables that I'm referencing to create my custom table. Mysql Dump File Finally if you wish to take a look here is my mysql dump file you can download and dump into your test db. http://www.mediafire.com/?op7ku1mk4erp4m6 Thanks for any help in advance. Edited December 4, 2011 by sbsmith Quote Link to comment Share on other sites More sharing options...
sbsmith Posted December 8, 2011 Author Report Share Posted December 8, 2011 This has been resolved by replacing COUNT(domain) AS domain_count On second line with COUNT(DISTINCT domain) AS domain_count without using DISTINCT on COUNT It seems to be counting my domains again which in turn gives me the incorrect number. I don't fully understand why it was behaving like this but at least it is finally working the way I intended. Quote Link to comment Share on other sites More sharing options...
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