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Strict standards: Only variables should be passed by reference


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This has to do with the version of PHP. 

You should paste the PHP code in question, like the 5-10 lines around the error, not the whole page.

That said, and not having looked at the code, it is probably because the code is passing in a function result, as the argument, into another function. So you fix this by creating a variable out of the function call, and pass the variable into the function. 



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