# Line slope calculator x-5y=-2

**Straight line given by points A[3; 1] and B[8; 2]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+0.4

**Canonical form of the line equation:**x-5y+2 = 0

**Parametric form of the line equation:**

x = 5t+3

y = t+1 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -2

**Y intercept:**y

_{0}= q = 0.4

**Distance line from the origin:**d

_{0}= 0.3922

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[5.5; 1.5]

**Perpendicular Bisector equation:**5x+y-29 = 0

**Vector OA = (3; 1) ; |OA| = 3.1623**

**Vector OB = (8; 2) ; |OB| = 8.2462**

**Scalar product OA .OB = 26**

**Angle ∠ AOB = 4°23'55″ = 0.0768 rad**