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  1. My PHP script for mysqli queries works most of the time, but while running a loop that queries database many times, occasionally I'll get Warning: PHP Warning: mysqli_stmt::execute(): (HY000/2013): Lost connection to MySQL server during query in... blah blah blah Can someone tell me if I need to modify the structure of my queries to make it work better? Here's my example: <?php $host = "localhost"; $username = "blah_blah"; $password = "blah_blah"; $database = "blah_blah"; $mysqli = new mysqli($host, $username, $password, $database,0,'/var/lib/mysql/mysql.sock'); $mysqli->
  2. Hi, I am developing a php-mysql website hosted in an apache. The site is down since yesterday for my IP address, whereas it is visible elsewhere. The web hosting company said they do not see any problems and my IP is not blocked by them. The problem has occured before and was solved by itself after a few days. I simply do not understand the reason behind it. Annoying as I have to stop working on the site till it is restored. Please help. Cheers.
  3. How do I style this table to make it look "prettier" I have tried a little with css and html tags with no luck. // display data in table echo "<table border='1' cellpadding='10'>"; echo "<tr> <th>ID</th> <th>First Name</th><th>Middle Name</th> <th>Last Name</th><th>Client ID</th><th>Diagnosis</th><th>Gender</th><th>Level of Care</th><th>Counselor</th><th>Active</th><th>Aftercare</th></tr>"; // l
  4. I have received so much help from this site and the amazing people on it. I am humbled by the amount of knowledge everyone here has. I am hoping that you can help me with something that I am struggling to figure out. I have a check box that successfully writes to my db but I can only get it to work with 1 and 0. I would like checked = yes unchecked to = no but I cant figure it out. Here is the code I am currently using. <strong>Active: *</strong> <input type="checkbox" name="Active" value="1" <?php if($Active == 1) echo 'checked="checked"'; ?>"/><br/> an
  5. Is it possible to have 2 or 3 tables in a database example Table 1 = names Table 2 = address Table 3 = phone numbers and when I fill in my name and number on a form it writes the name to the name table and number to the number table and then I can build a query to pull the phone that goes with the right name? Is it better to spilt it up this way for security or it doesn't really matter? I just feel like I have way to many rows in a single table on my database.
  6. I am using the code from Basic PHP System: View, Edit, Add, Delete records with MySQLi and I am wanting to add some code that will display a total number of results returned from a query. if ($result = $mysqli->query("SELECT * FROM clients where (`clients`.`aftercare` = 'yes')ORDER BY LastName ASC")) My question is how can I display how many records are returned. So for example I run it and it returned 40 names. I would like to add something to the page that says 40 people found. I am sure this is probably very simple, but I am brand new to all of this. Thank you for you help in advance.
  7. Hello Forum: I'm just now trying to learn PHP and read that using PDO was a better way to utilize online databases. I have my Registration page completed, storing client info in a MySQL db, all done using PDO. However, I'm having a little trouble with the Login page. I don't know if I'm using the PDO stuff the right way. $stmt = $db->prepare('SELECT (username, password) FROM members WHERE (username) LIKE ? AND (password) LIKE ?'); $stmt->bindValue(1, "%$uname%", PDO::PARAM_STR); $stmt->bindValue(2, "%$pwd1%", PDO::PARAM_STR); $stmt->execute(); echo $a
  8. Hello, i try to make an Ajax pagination, but I got error. Here is my code : Here is My Panel Controller : <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class Panel extends MY_AuthController { public function __construct() { parent::__construct(); $this->load->model("paneldata"); } public function index() { $this->load->view('template/header/panel.php'); $this->load->view('containt/panel.php'); $this->load->view('template/footer/panel.php'); } public function general_post($awal = 0) { $this->
  9. Hi there, i have recieved this notice Warning: Header may not contain more than a single header, new line detected in C:\xampp\htdocs\a\Student_Edit_Handler.php on line 53 and these are my codes. Kindly help me to fix this. <?php session_start(); $session_id = $_SESSION['user_id']; if($session_id == null){ header("location:Student_Edit.php"); die(); } include 'Connect.php'; $flag = "success"; function rollbackData(){ mysql_query(" ROLLBACK "); global $flag; $flag = "error"; if(mysql_error() != null){ die(mysql_error()); } } $student_id = $_POST['student
  10. Hello everyone, I am confused with these little codes why it keeps error in updating the learner information. These are my codes so far. These are the bits of Student_Info.php which i think would be useful in my query. <?php if(!empty($_GET['flag']) && $_GET['flag'] == "success") { ?> <span class="stylered style1"><span class="style5">Learner Information updated successfully.</span></span> <?php } else if(!empty($_GET['flag']) && $_GET['flag'] == "error") { ?> <span class="stylered style3 style5"><s
  11. Hello there Admins, I would like to display the image on his/her profile. This is so far the codes i have made. It displays only the outline border of the image but not the student's image itself. <?php session_start(); $session_id = $_SESSION['admin_id']; if($session_id == null){ header("location:Admin_Home.php"); die(); } include 'Connect.php'; $student_id = htmlentities($_REQUEST['id'], ENT_QUOTES); $result = mysql_query("SELECT * FROM student_information where student_id='$_GET[id]'"); $data = mysql_fetch_array($result); $numRows = mysql_numrows
  12. Good day Php Friends, i have manage to make a searchbox which displayed the student according to their first name. But after it is being displayed i added with view, edit, delete links. Now my problem is when i click the links it will not direct to the specific student. here are the code for your reference. Admin_Home.php </head> <?php include 'Header.php';?> <body> <script language="javascript" type="text/javascript"> function ajaxFunction(){ var ajaxRequest; try{ // Opera 8.0+, Firefox, Safari ajaxRequest = new XMLHttpRequest(); }catch (e){
  13. I am trying to use JSONReader (along with PHP & XPATH) to parse a very large JSON file, then display search results. A stream parser (such as JSONREader) is recommended over JSON_decode when parsing large files. This simple code below is not displaying any results (in the echo statements). Any advice is greatly appreciated. $reader = new JSONReader(); $reader->open('products.json'); $dom = new DOMDocument; $xpath = new DOMXpath($dom); while ($reader->read() && $reader->name !== 'product') { continue; } while ($reader->name === 'product') { $node = $do
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