If you are working with a PNG, you should be able to open it up in Photoshop and add a new layer below the image and fill that with whatever background color you need. Any antialiasing should adapt automatically to the new background color.

You have a link to the image you are talking about?

Ummm... nevermind. I misread your comments and thought you were trying to do something else. Here are the proper steps:

Steps:

1 -- open the file in Photoshop
2 -- create a new layer above "layer 0" (which contains the original PNG), and name it "match"
3 -- using the pencil, paint in a small spot of the #33ffcc color on the "match" layer. This is just for matching later.
4 -- duplicate "layer 0", and place it between layer 0 and the "match" layer you just created in step 2. Rename the layer "copy" just for clarity's sake
5 -- select the duplicated layer, and then adjust the colors using Image > Adjustments > Hue/Saturation until it nearly matches the color you are looking for (the blue circle includes a gradient, so it won't be exactly #33ffcc). Compare it to the #33ffcc in the "match" layer. This will mostly be done by adjusting the "Hue" slider.  Make sure that the "preview" checkbox is on, so you can see what your changes will look like.
6 -- once you have adjusted it to your liking, do a Save for Web

Make sense?

No, the steps are the same. Hue/Saturation will adjust the gradient.  You'll see what I mean when you actually try it.

you could set the default value using

<input value="default value here..." ... etc

and then clear it on click with javascript:

<script language="JavaScript" type="text/JavaScript">
function clearDefault(field) {
if (field.defaultValue==field.value) { field.value = ""; }
}
</script>

<input type="text" name="name" value="name" onFocus="clearDefault(this)">

Oh I put the wrong link in. here it is. http://www.456bereastreet.com/archive/2 … avascript/

I agree though - too much code. I'll try yours - if it works - I'm using it! Thanks again, again! 456bereastreet was making it more assessable I think - hence all the code. But that's not worth all the code to me...