Killersites.com Web Design Forums

Radio Button Help, need one button to disable other buttons

dummy@example.com (jlhaslip) — Sat, 21 Nov 2009 07:11:47 +0000

Hey guys, I have a "submit Support Ticket" form that is built up of about 20 radio buttons and all my services. Witch looks something like.. ( O represents a radio button ) Service Type: | O In home O Drop off ------------------------------------------------------------ Service: | O Computer repair | O othr service | O Other service | O wireless network setup Now, most of my services can be done both in home and by drop off. However things like wireless network setup must be done in home. I would like to make it so that when the user checks the "in home" box, they are not able to select these services. I have had a few ideas on how i could go about doing this but i would like some other opinions before i do anything. At the moment i have it return as a form error, so if they have checked say, "Drop Off" Service type.. and "wireless network setup" as the service. It submits the form but than sends the user back saying "Error this service cannot be done in home", id like it to happen before they submit the form. (this is also posted in javascript, but id really like to find a way to do it in php)

PHP include() not diplaying contents

dummy@example.com (jlhaslip) — Sat, 21 Nov 2009 07:03:52 +0000

[b]EDIT[/b] Okay, this PHP crap has left my brain in a pretzel. I figured out a way to get the same effect with iframes, so I'm just not going to use the PHP include function. When, if ever, I really have to use it, I'll figure it out then. Anyway, I really appreciate the help from everyone. This is the best web coding forum ever! :D [quote] Hello, I recently learned about PHP includes() and decided to try and use it on a header and footer for a website I'm building. I saved the header contents as a PHP file, and I put the include code into my index.htm page with the correct path name. But for some reason, when I view the index.htm document it doesn't display the contents of header.php. It doesn't give me an error either. I tried to upload it to my hosting to see if it would work then, but again just a blank page. This wouldn't be the first time PHP has stumped me, and I really appreciate the help. :) My header.php code: [code]

[/code] The PHP include() code in the index.htm document: [code]

[/code] Thanks again, -Raven [/quote]

Counting the number of rows??

dummy@example.com (delirium) — Sat, 21 Nov 2009 04:09:26 +0000

Hey guys, im trying to get my webpage to display the number of "support tickets" that the user has. Here is the code(session->username is self explainitory): $getstickets = mysql_query( "SELECT * FROM `sticket` WHERE `username` = '$session->username'" ); $result = mysql_query($getstickets); mysql_num_rows($result); echo mysql_num_rows($result); But it keeps saying mysql_num_rows() supplied argument is not a valid mySQL result resource. Can anyone tell me what im doing wrong?

PHP pagination

dummy@example.com (jlhaslip) — Fri, 20 Nov 2009 02:30:37 +0000

I found this guide on how to create a paginated image gallery in PHP. I have adapted it to suit my needs, but there is one bit which is completely stumping me. I reckon you'd have to read it all to be able to help me, so please do, if you have the time: [url]http://www.lateralcode.com/simple-php-gallery-pagination/[/url] The bit which is confusing me is: $count = 0; $skip = $page * $per_page; while ( $count < $skip && ($file = readdir($handle)) !== false ) { if ( !is_dir($file) && ($type = getPictureType($file)) != '' ) $count++; } the reason is, on the next line, it resets $count to 0, so the above loop to me seems pointless. I took it out and re-ran the code and it breaks so it is needed. But all it does is increment count until count equals skip and then it is reset on the next line anyways. i think the main reason im getting so confused is that the article isn't explaining it wel enough, perhaps because they don't expect the reader to be a noob, ha. help me someone please :(.

Resize pictures

dummy@example.com (falkencreative) — Thu, 19 Nov 2009 17:23:37 +0000

Hello, I created a page where I display a picture using the following script: Where 'picture' is the record that contains the name of the picture, for example: mypicture.jpg Those pictures are first uploaded to the ../pictures/ directory. Until know I have to manually resize them to a fixed width. How could I tell php to resize those pics automatically to that same fixed width (with the same ratio of course), so I can upload the pics without having to pre-resize them? Thanks Eduardo

php Jon Lebensold Shopping Cart

dummy@example.com (shaman) — Wed, 18 Nov 2009 14:21:23 +0000

Hi, I need HELP i'v finished the shopping cart and all works fine, which is forselling food, but i wanted to add another xml for selling some wines, i am struggling with this i also wanted a home page with links to the food page and the wine page, Best Regards. hope someone can help please.:)

MY PHP WEBSITE

dummy@example.com (synbitz) — Mon, 16 Nov 2009 19:26:37 +0000

I made this website, full PHP driven using a MYSQL database : http://ww w.webh ost-choice.c om [remove spaces] what do you think? thnx

How to transfer database from older website to newer one

dummy@example.com (falkencreative) — Sun, 15 Nov 2009 20:59:43 +0000

Hi everyone I have a database with some tables in a website. Now our company decided to open a new website and permanently delete the old one. Will anyone tell me how to transfer that database form older site to the newer one? The data is too important and I do not want to lose it anyway.

Injecting Field from a Database into a Textfield Form

dummy@example.com (falkencreative) — Sat, 14 Nov 2009 17:05:30 +0000

Hi Everyone! :) I just have a question regarding Object Orientated PHP if anyone is experienced with that concept. well..i have a gui page and a controller page for functions and sql queries. i like to think that people can learn the more they practice. how true indeed. Issue is that i want to show the value of one single field from the database into a textfield value. then i wasn to be able to update the message by submitting that button. i had it working the other day but i've gone blank as to what ive done wrong here. Admin Controller [code] function getCurrentMessage($strMessage = "") { $this->strMessage = $strMessage; $DBA = new DBAccessor("localhost","root","root", "dblw") or die ('cannot connect to database error: '.mysql_error()); $DBA->dbConnect(); $sql = mysql_query("SELECT `tablescrollingmessage`.`strMessage` AS `strMessage` FROM `tablescrollingmessage`"); while($row = mysql_query($sql)) { extract($row); } $DBA->dbClose(); return $strMessage; } function messageSaved($currentMessage) { $DBA = new DBAccessor("localhost","root","root", "lwdb") or die ('cannot connect to database error: '.mysql_error()); $sql = 'UPDATE `tablescrollingmessage` SET strMessage='.$currentMessage.';'; //Connect to the database and execute the query $DBA->dbConnect(); $result = mysql_query($sql); $DBA->dbClose(); } [/code] GUI Form [code] getCurrentMessage($strMessage); $mesg1 = new AdminController; $mesg1 = $mesg->messageSaved($currentMessage); $mesg = $_POST['strMessage']; ?>

Problem with page redirecting: header("Location: $url");

dummy@example.com (quyen) — Fri, 13 Nov 2009 05:27:48 +0000

Hello everybody, This is a warning i've got whenever I use [color=red] "header("Location: $url"); "[/color]. [color=red] Warning: Cannot modify header information - headers already sent by (output started at C:\Inetpub\vhosts\qwebdesign.net\httpdocs\admin\index.php:15) in C:\Inetpub\vhosts\qwebdesign.net\httpdocs\admin\user_manager.php on line 319 [/color] Is there any solution to redirect to a url without using "header("Location: $url"); Or somehow I can fix the above problem? I've been reading some topics on some websites, and they are all about how to use header("Location: $url"); but i haven't found any right answer for my situation. [color=red]Note[/color]: "header("Location: $url");" runs ok on localhost at my computer, I only got this problem when I upload my project to a hosting. Thank a lot for helping me! Quyen,

Help with if/else in DELETE

dummy@example.com (quyen) — Thu, 12 Nov 2009 18:55:18 +0000

Hello, Sorry to bother you guys. If l have a variable called $value and this value fetches array from my database. ex. $xyz=mysql_query("SELECT contentext FROM blablabla WHERE parent is NUTLL); foreach($xyz as $value =>$key){ echo $value[1][0]['contenttext']; //where 0 is my error messages and 1 is my reuslt } then, l have $xyz2=mysql_query("SELECT contentext FROM blablabla WHERE is_campaign is NOT NULL AND parent IS NOT NULL); foreach($xyz2 as $value2 =>$key2){ echo $value2[1][0]['contenttext']; } So now if l am working on two different delete buttoms. I will like the delete.gif to be red if nothing is in the $value. l went this way: if(is_num($value > 0){ echo " you can not delete since the $value has a $value2 contents in it"; }else{ echo " You can delete this $value 2 since it contains no $value content"; } This is not working mich for me. Any tip on doing this ? Thanks

HELPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!

dummy@example.com (Lawanson) — Mon, 09 Nov 2009 09:45:25 +0000

I designed and tested out a form that sends it's results to an email and it worked perfectly well before i tried to add an image uploader which i had some bugs with. I then decided to cancel the image uploader field in the form and optrd to redirect the user to an image uploader page which i created seperatlely after the form has been submitted to the specified email. But after doing this, i noticed that the stupid form would no longer process information but instead it gives me an error page like this, "The requested method POST is not allowed for the URL /sendresults.php". The php script i use for processing the form is $value) { if ($req == '1') { if ($value == '') {echo "$key is empty";die;} } $j = strlen($key); if ($j >= 20) {echo "Name of form element $key cannot be longer than 20 characters";die;} $j = 20 - $j; for ($i = 1; $i <= $j; $i++) {$space .= ' ';} $value = str_replace('\n', "$line", $value); $conc = "{$key}:$space{$value}$line"; $text .= $conc; $space = ' '; } mail($emailadd, $subject, $text, 'From: '.$emailadd.''); echo ''; ?> Please am i doing something wrong?

quick easy php validation question?

dummy@example.com (administrator) — Sun, 08 Nov 2009 13:33:00 +0000

Im putting in url validation. Is this... if (preg_match("/^(http(s?):\/\/|ftp:\/\/{1})((\w+\.){1,})\w{2,}$/i", $website)) { echo "Valid URL"; } else { echo "Invalid URL"; } the same as this... if (!preg_match("/^(http(s?):\\/\\/|ftp:\\/\\/{1})((\w+\.)+)\w{2,}(\/?)$/i", $website)) { header( "Location: $errorurl" ); exit ; } Note, I just added the "!" infront of preg_match and went strait to the error. Am I right here?

How Does This Code Work??

dummy@example.com (delirium) — Thu, 05 Nov 2009 17:21:29 +0000

Hey, im starting to get really into php but im not completely familiar with all the code yet. I had my cousin type this up for my login system and its a comment/Guestbook thing. It works but im really not sure how and i would love to understand whats happening in this code. Could anyone please go through the code and explain whats happening? The code is below, but here is an example of what im looking for.. $message = htmlspecialchars(addslashes("$_POST[message]")); **This sets the variable "$message"** Ideally i would like en explanation like that for every line, thanks so much in advance. ______________________________________________________________________________ //submit comment switch ($_GET['page']) { case 2: if(isset($_GET["sign"])) { $message = htmlspecialchars(addslashes("$_POST[message]")); $time = date("F j, Y, g:i a"); $querty = mysql_query("INSERT INTO guestbook(owner,postedby,post,time) VALUES('$req_user','$session->username','$message','$time')");echo "Your message has been posted
"; } else {echo ( "Message was not posted" ); // or no request sent } break; } // Display comment system $req_user = trim($_GET['user']); $getcomments = mysql_query( "SELECT * FROM `guestbook` WHERE `owner` = '$req_user' ORDER BY `ID` DESC" ); while ($comments = mysql_fetch_array($getcomments)) { echo "$comments[postedby] ($comments[time]) - $comments[post]
"; } //Display comment submit box echo "
Sign $req_user's guestbook
"; /* Link back to main */ echo "
Back To [Main]
"; ?> This is the line i really dont get,

Change the date format Mysql - php

dummy@example.com (edoplaza) — Thu, 05 Nov 2009 13:16:21 +0000

Hello, I'd like to change the date format from my DB (yyyy-mm-dd) to dd-mm-yyyy using php. Here is the url: http://ww w.germanmarcano.com/eventos/indexEnglish.php Here is the code: [code] Events

Events

Date:
Place:
Time:

[/code] Thanks Eduardo